12x^2+74x-104=0

Solution for 12x^2+74x-104=0 equation:

12x^2+74x-104=0

a = 12; b = 74; c = -104;
Δ = b2-4ac
Δ = 742-4·12·(-104)
Δ = 10468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10468}=\sqrt{4*2617}=\sqrt{4}*\sqrt{2617}=2\sqrt{2617}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-2\sqrt{2617}}{2*12}=\frac{-74-2\sqrt{2617}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+2\sqrt{2617}}{2*12}=\frac{-74+2\sqrt{2617}}{24}
$